Optimal. Leaf size=32 \[ -\frac {1}{275 (5 x+3)}-\frac {49}{242} \log (1-2 x)+\frac {68 \log (5 x+3)}{3025} \]
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Rubi [A] time = 0.01, antiderivative size = 32, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {88} \begin {gather*} -\frac {1}{275 (5 x+3)}-\frac {49}{242} \log (1-2 x)+\frac {68 \log (5 x+3)}{3025} \end {gather*}
Antiderivative was successfully verified.
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Rule 88
Rubi steps
\begin {align*} \int \frac {(2+3 x)^2}{(1-2 x) (3+5 x)^2} \, dx &=\int \left (-\frac {49}{121 (-1+2 x)}+\frac {1}{55 (3+5 x)^2}+\frac {68}{605 (3+5 x)}\right ) \, dx\\ &=-\frac {1}{275 (3+5 x)}-\frac {49}{242} \log (1-2 x)+\frac {68 \log (3+5 x)}{3025}\\ \end {align*}
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Mathematica [A] time = 0.02, size = 30, normalized size = 0.94 \begin {gather*} \frac {-\frac {22}{5 x+3}-1225 \log (1-2 x)+136 \log (10 x+6)}{6050} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(2+3 x)^2}{(1-2 x) (3+5 x)^2} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [A] time = 1.36, size = 37, normalized size = 1.16 \begin {gather*} \frac {136 \, {\left (5 \, x + 3\right )} \log \left (5 \, x + 3\right ) - 1225 \, {\left (5 \, x + 3\right )} \log \left (2 \, x - 1\right ) - 22}{6050 \, {\left (5 \, x + 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.01, size = 43, normalized size = 1.34 \begin {gather*} -\frac {1}{275 \, {\left (5 \, x + 3\right )}} + \frac {9}{50} \, \log \left (\frac {{\left | 5 \, x + 3 \right |}}{5 \, {\left (5 \, x + 3\right )}^{2}}\right ) - \frac {49}{242} \, \log \left ({\left | -\frac {11}{5 \, x + 3} + 2 \right |}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 27, normalized size = 0.84 \begin {gather*} -\frac {49 \ln \left (2 x -1\right )}{242}+\frac {68 \ln \left (5 x +3\right )}{3025}-\frac {1}{275 \left (5 x +3\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.45, size = 26, normalized size = 0.81 \begin {gather*} -\frac {1}{275 \, {\left (5 \, x + 3\right )}} + \frac {68}{3025} \, \log \left (5 \, x + 3\right ) - \frac {49}{242} \, \log \left (2 \, x - 1\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.09, size = 22, normalized size = 0.69 \begin {gather*} \frac {68\,\ln \left (x+\frac {3}{5}\right )}{3025}-\frac {49\,\ln \left (x-\frac {1}{2}\right )}{242}-\frac {1}{1375\,\left (x+\frac {3}{5}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.15, size = 26, normalized size = 0.81 \begin {gather*} - \frac {49 \log {\left (x - \frac {1}{2} \right )}}{242} + \frac {68 \log {\left (x + \frac {3}{5} \right )}}{3025} - \frac {1}{1375 x + 825} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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